MHD721S - Materials Handling 324 - 1st Opp - Nov 2022


MHD721S - Materials Handling 324 - 1st Opp - Nov 2022



1 Pages 1-10

▲back to top


1.1 Page 1

▲back to top


nAm I BI A u n IVE RS ITV
OF SCIEnCE Ano TECHnOLOGY
FACULTYOF ENGINEERINGAND BUILTENVIRONMENT
DEPARTMENT OF CIVIL, MINING AND PROCESSENGINEERING
QUALIFICATION: BACHELOR OF MINING ENGINEERING
QUALIFICATION CODE: 08BMIN
LEVEL: 7
COURSE CODE: MHD721S
COURSE NAME: MATERIALS HANDLING 324
SESSION: NOVEMBER 2022
DURATION: 3 HOURS
PAPER: THEORY
MARKS: 100
EXAMINER(S)
MODERATOR:
FIRSTOPPORTUNITYQUESTION PAPER
Mr H.K Hengari
Mr L. Madziwa
INSTRUCTIONS
1. Answer all questions.
2. Read all the questions carefully before answering.
3. Marks for each question are indicated at the end of each question.
4. Please ensure that your writing is legible, neat and presentable.
PERMISSIBLEMATERIALS
1. Examination paper.
2. Calculator and appropriate stationery
THIS QUESTION PAPER CONSISTS OF 8 PAGES (Including this front page)

1.2 Page 2

▲back to top


1.3 Page 3

▲back to top


Question 1 [15 marks]
Acquiring equipment for a specific mining operation is one of the major concerns of mine
planning. Equipment can be bought, rented, or leased.
a) State five (4) advantages of buying machinery over the other methods of
procurement. (4 marks)
b) Consider a dozer with an ownership cost of N$ 238.20 per hour. Cost is based on
assumption that the machine will work 2400 hours each year of its service life.
Checking with a local rental company, the mine receives rental quotes of N$ 40 000
per month {168 hrs), N$15 600 per week (40 hrs), and N$ 5000 per day (9 hrs). What
are the breakeven working hours for all four options? {16 marks)
Question 2 [20 marks]
A 15.8 m3 shovel is used to load poorly blasted rock (1.65 t/m 3, bucket fill =0.85). Consider
loading a CAT 777D truck, with a heaped volume of 60.1 m3 and a maximum payload of 90.4
tonnes. The shovel bucket swing cycle time is 49 seconds. Dump time is 1.2 minutes. The
haul distance is 7.7 km from the face to the dumping point. The ramp is 1.3 km, with a
gradient of 10%. The rolling resistance of the haul road will be maintained at 5%. Both
machines operate on a 50 min/hr efficiency.
a) How many buckets are needed to fill the truck? Perform a gravimetric check on the
number of buckets you select (3 marks)
b) Estimate the cycle time of the truck and the balanced number of trucks (10 marks)
c) What is the overall mine production in tonnes per hour? (3 marks)
d) Discuss two (2) modifications will you make to the truck-shovel operation to increase
production, without changing the size of the units. (4 marks)
Question 3 [20 marks]
Given the following data work out the design parameters of a friction sheave hoist:
Two balanced skips, tower mounted hoist.
Production rate = 500 tonnes/hr
Shaft depth = 600m
Headframe height= 30m
Hoist rope 4 flattened stranded
Skip weight= 13 tonnes
live load =13 tonnes
Hoist speed = 4 m/s
Load time = dump time = 6 sec
Acceleration = retardation = 1.29 m/s 2
Calculate the following:
a) Minimum rope diameter to be used in this operation (5 marks)
b) Rope slippage, if the friction ratio should be below 1.6. (5 marks)
c) Sheave diameter and tread pressure (5 marks)
d) Horsepower to accelerate the suspended load (5 marks)
2

1.4 Page 4

▲back to top


1.5 Page 5

▲back to top


Question 4 [20 marks]
A 1200 mm wide conveyor belt is to be designed for coal (SG=0.96) haulage up a 600 m-
long 5° slope. The peak capacity is estimated to be 1,000 tph, and the belt speed will be set
at 3 m/s. The belt drive will have a counterweight, lagged pulley, and a 240° arc of contact.
Due to high production rates, consider heavy-duty operations.
a) Estimate the required tensions on both sides of the belt. (10 marks)
b) If the maximum allowable sag of the belt is 0.02 m, will 1.5 m and 3 m spacing for
the carrying and return idlers be sufficient to support or will additional tensioning be
required (6 marks)
c) Calculate the Allowable tension of the belt to suit this operation (2 marksj
d) If motor drive efficiency is assumed to be 90%, determine the power required. (2
marks)
Question 5 [20 marks]
In an underground mine, water must be pumped from the working. There are 650 m
between the water source to the shaft. From there, there is a vertical height of 590 m. The
mixture of water and solids has a density of 1.36 t/m 3•
a) How many pumps are needed to pump this water if the maximum power rating of
the pump available is 50 kW? The pumping rate is assumed to be 0.05 m3/s. The
piping to be used has a diameter of 139 mm and a friction factor of 0. 0084. All the
coupling and fittings in the system have KL= 6.5. The efficiency ofthe pump is 80%
and the motor that drives it at 84%. (10 marks)
b) What improvements can you suggest for this design? (5 marks)
c) What are the benefits of pit dewatering in mining operations? (5 marks)
3

1.6 Page 6

▲back to top


1.7 Page 7

▲back to top


Te=Ti-Tz
T1+T2
p= NDd
TSL x V2
HP1=
77gta
pgHQ
P=--
1J
Formula Sheet
Q
m-
G-
3. 6V
SF- 25000
4000 +H
. Tmax
Tension=~
s
P= (1 + 011
Pi
EAC=
on) ( 1 - (1:
Te= T2 K
d~ JN(fj~«,H)
TeV
PA=-
1J
flvz
hi=-+KZig-d
vz
TSL = We + W0 + 2Ws
Zg
+2WR
Tcmin
=
l~(mb
+
8S
mG)g
TC
BP=- LT
Trmin
=
l';.(mb)g
8S
60
Truck Load X # of Trucks X TC X jF X p
Te = af Lg{midlers + (Zmb + me) cos o} + Rs + mcgL sin o
C ---
-~--
Operating Conditions
-~
I 'Belt Width
(mm)
Belt Width
(in)
Light Duty
kg/m
Medium Duty Heavy Duty
kg/m
kg/m
500
600
750
900
1050
1200
20
I 24
30
36
42
,------
48
(lb/ft)
4.1 (2.75)
I 5.0 (3.36)
6.2 (4.16)
I 7.4 (4.97)
8.6 (5.78)
9.8 (6.58)
I (!b/ft~-
I
I
6.2 (4.16)
I 7.4 (4.97)
9.3 (6.25)
I 11.1(7.46)
13.0(8.73)
14.8 (9.94)
(lb/ft)
10.3 (6.92) I
I
I
-~
12.3 (8.26)
iI 15.5 (10.41)
11
18.5(12.43)
! 21.6(14.51)
24. 7 (16.60)
1350
1500
54
60
11.0 (7.39)
12.3 (8.26)
Ir 16.7 (11.22)
18.6 (12.50)
27.8 (18.68)
30.9 (20.76)
1650
1800
66
I 72
13.5 (9.07)
----14.7 (9,88)
20.5 (13.77) 33.9 (22.78)
I 22.3 c14.98) 37.o (24.86)
-- - -
a
-
4

1.8 Page 8

▲back to top


1.9 Page 9

▲back to top


Belt Width Belt Width
(mm)
(in)
450
18
600
20
750
24
900
30
1050
36
1200
1350
42
48
1500
54
1650
60
-- 1800
2100
2200
-6-6--·
72
84
Mass of Moving Parts (kg/m) (lb/ft)
Light Duty
4" Idlers
Light Belt
Medium
Duty
5" Idlers
Moderate
Belt
Heavy Duty
6" Idlers
Heavy Belt
Extra Heavy
Duty
6" Idlers
Steel Cord
Belt
23 (15.4) 25 (16.8) 33 (22.2)
29 (19.5) 36 (24.2) I 45 (30.2)
49 (33.0)
37 (25.0) 46 (31~
57_(38.3)
63 (42.3)
45 (30.0) 55 (37.0) 70 (47.0)
79 (53.0)
52 (35.0) 64 (43.0) 82 (55.0)
94 (63.2)
63 (42.3)
70 (47.0)
71 (47.7) 95 (63.8)
82 (55.0) 107 (72.0)
·-1 110 (74.0)
127 (85.3)
91 (61.2) 121 (81.3) 143 (96.0)
-
100 (67.2) 132 (88.7) 160 (107.5)
144 (96.7) 178 (119.6)
·-
I
168 (112.8) j 205 (137.7)
177 (119.0) 219 (147.2)
ARC OF CONTACT
10...--1
Single pulley
•100
·210
·220
0 230
•240
270
Tandem Pulley
360
390
•420
•440
•450
•450
'180
TABLE 1
STANDARD DRIVE FACTOR "K" VALUES
COUNTERWEIGHT TAKE-UP
Berwputl•Y
µ •0.30
Lllggedpullav
µ•0.35
SCREW TAKE-UP
e,rwpull-v
Far 20% hlgh,r T 1
L9gged pull-v
Far 2°" hlllh•r T 1
0.64
0.50
0.97
0.90
0.50
0.38
0.80
0.66
0.46
0.35
0.76
0.63
0.43
0.32
0.72
0.59
0.40
0.30
0.68
0.56
0.32
0.24
0.58 ----~·
0.49
0.18
0.13
0.42
0.36
0.15
0.11
0.39
0.33
0.13
0.09
0.36
0.31
0.11
0.07
0.34
0.30
0.11
0.07
0.33
0.29
0.09
0.06
0.32
0.29
0.09
0.06
0.31
0.27
Arc af contact commonly m•t in actual practice
Rapedesign Rope Weight (kg/m)
Round Strand 0.0036d 2
Flat rope
0.004ld 2
Locked coiled 0.0056d 2
0.59d 2
0.63d 2
o.ssd2
5

1.10 Page 10

▲back to top


2 Pages 11-20

▲back to top


2.1 Page 11

▲back to top


I
J
-
I
I
I
I
I
100 iLock,gd•' con:drum & Koe(e
__.,/.
I
:
I
90 i
I
.,,,_,/,.~
.----if'
I
.e
60
!
I
I
1._ij
I
I
'"5E-,i
D
7U I
I
I
60 !
5D
I
!
Rounds!F.nd& llartenedslramJ•KocpeJ
...-,,- ... -
-
i
_.,.-..-,,./
I ~'==r= tIl;,-..,,../."..-,-./-
Ii
--
-
...
Ho1u11S1'ir.n1nd& filaUenIedstrari.d·d.tu1l
i
i
I
I
I
II
-
J
·1
-ii
100-0
.200H
31'JDD 40t:HJ·
oepmm_.J. tr ~•
I
I
Q
7i:1_,ocm-
i 6MOO~
17tJ.00{t
I
I
I 1 6".),(_\\{1(1
I
- 1- 114000,1.,Q(W[J(CI .........I....--LS. 'tnugfi~lereO.:1:r~uuum1..._..
,_ =
~3CUJIKt~I
Ko\\:te;:;,
'- ·-"'- I
I
=!
J
:/
"' -~_•,1 I
I '-l
! "- ' B'Jr,1}00
- I
W.000
v- ~- eJ,_ooc, I-
~'),iJO.':•
_J 4fi_!)0{)
~/r r)j•,(10-0
/
ai,.rn:10
rV- I i w.om:,
n I'--
ii
I
',,/
/~ ..,.J.
/
/
")( I
,r
,•'I'"
[ I ..--r '·-,.J_,...,; /
/,,,-'
V
!i
b/l
1,.,-'
;,-
I/
V.......-1[.,...,.-.--~---LjM !/I 1
I
I
I
I
_j______
Drnm di.arneterft-t~ l111eteri
3
6

2.2 Page 12

▲back to top


2.3 Page 13

▲back to top


2.S
2.0
I.S
, •1
1,05
,.o
10
Iv.:~
V,
I':
,~,f'-
o._...
\\
\\
r'\\
' t\\.
' !"I
"I'"
'
20 30 50 100 200
1000
CONVEYORLENGTH(DISTANCEBETWEEN CENTRES J,L
5000m
7

2.4 Page 14

▲back to top


2.5 Page 15

▲back to top


• - - - - Typical Field Empty Weight
"• • • •• • • • • 163 360 kg (360,143 lbl Load
kg X
1000
50
40
30
20
20
30
I
50
I
GrossWeight
40 50
II
100
II
60 80 100
I I
I
I I 150 200 kg x 1000
I I II
I 150 200 250 300 400 5001b x 1000
I 111111111
II II
I
10
__,,
:a::.:., 5
=:5 3
2
1
0.50
0.30
TorqueConverterDrive • • •
Direct Drive
0.5
0 5 10 15 20 25 30 35 40 45 50 mph
I
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 km/h
SPEED
8

2.6 Page 16

▲back to top