ASS801S - APPLIED SPATIAL STATISTICS - 2ND OPP - JULY 2023


ASS801S - APPLIED SPATIAL STATISTICS - 2ND OPP - JULY 2023



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nAmlBIA UnlVERSITY
OF SCIEnCE Ano TECHnOLOGY
FACULTYOF HEALTH,NATURALRESOURCESAND APPLIEDSCIENCES
SCHOOLOF NATURALAND APPLIEDSCIENCES
DEPARTMENTOF MATHEMATICS, STATISTICSAND ACTUARIALSCIENCE
QUALIFICATION:Bachelor of ScienceHonours in Applied Statistics
QUALIFICATIONCODE: O8BSHS
LEVEL: 8
COURSECODE: ASS801S
COURSENAME: APPLIEDSPATIALSTATISTICS
SESSION:JULY 2023
DURATION: 3 HOURS
PAPER:THEORY
MARKS: 100
SUPPLEMENTAR/YSECOND OPPORTUNITYEXAMINATION QUESTIONPAPER
EXAMINER
Dr D. NTIRAMPEBA
MODERATOR:
Prof G. 0. ORWA
INSTRUCTIONS
1. Answer ALL the questions in the booklet provided.
2. Show clearly all the steps used in the calculations.
3. All written work must be done in blue or black ink and sketches must
be done in pencil.
PERMISSIBLEMATERIALS
1. Non-programmable calculator without a cover.
ATTACHMENTS
1. Chi-square table
THIS QUESTION PAPERCONSISTSOF 4 PAGES(Excluding this front page & Chi-square table)

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Question 1 [20 marks]
1.1 (a) Briefly explain the following terminologies as they are applied to Spatial Statistics.
(i) Feature
[2]
(ii) Support
[2]
(iii) Local spillovers
[2]
(iv) Global spillovers
[2]
(v) Areal data
[3]
(b) State Tobler's first law of geography. Use this law to explain briefly what the influ-
ence of this law will be in Spatial Statistics.
[3]
1.2 Let X 1, ... , Xn be random variables in f2 . The symmetric covariance matrix of the random
vector X = (X 1 , ... , Xnf is defined by
E := Cov(X) = E[(X - E(X))(X - E(X)f]. Note that Ei,i = Cov(Xi, Xi)
(a) Show that Eis positive semi-definite.
[5]
(b) Define what it means for E to be a non-degenerate covariance matrix?
[1]
Question 2 [20 marks]
2.1 Consider a vector of areal unit data Z = (Z1, ... , Zn) relating to n non-overlapping areal
units. Additionally, consider a binary n x n neighbourhood matrix W, where Wkj = l if areas
(k, j) share a common border and Wkj = 0 otherwise.
(a) Define mathematically a Global Moran's I statistic and show how to compute the Z-score
associated to it.
[4]
(b) Data were obtained for the n 624 electoral wards in Greater London for 2009 on
the observed numbers of admissions to hospital due to respiratory disease(y, response vari-
able). Also collected were two covariates, the percentage of people defined to be poor (poor)
in each area, and the average air pollution concentrations (pollution) in each area.
(i) An initial simple Poisson generalised linear model was fitted to the hospital admission
counts (y), with both covariates and the (log) expected numbers of admissions as a known
offset term. The residuals were then tested for the presence of spatial autocorrelation, and
the results of a iVIoransI test are shown below.
Monte-Carlo simulation of Moran I:
Data: res
Weights: W.list
Number of simulations + 1: 1001
statistic=0.39417, observed rank=1001, p-value=0.000999
alternative hypothesis: greater
What does this test tell you about the presence or abscence of residual spatial autocorrela-
tion? Justify
[2]
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(ii) A Poisson log-linear Conditional Autoregressive(CAR) model was then fitted to these
data, where the linear predictor contained a set of random effects ¢ = (¢1, ... , ¢n) in addi-
tion to the covariates. The CAR model used has full conditional distributions given by,
I ~ ',fI'.i. ',fI'.-.i
N ( p I:p,"j=Ll j=WlkJW+i(j,lP-j
p)
,
p
I:,"
j=l
72
.
w,J
+(l-
p) )
, wl1ere m. t l1e usua l not at·1011 ',fI'.-.i
deno t es a11th e
spatial effects except the ith.
Output from fitting the model is given below.
Median 2.5% 97.5%
Intercept -0.8512 -1.2169 -0.4939
pollution 0.0074 0.0104 0.0258
poor 0.0267 0.0239 0.0259
tau 0.0798 0.067 0.0945
rho 0.8324 0.6825 0.9492
What does the estimated value of p tell you about the level of residual spatial autocorrelation
after adjusting for the covariates? Justify your answer
[2]
(iii) Calculate separate relative risks and 95% credible intervals for increases in each covariate
by 1 unit and interpret the results.
[6]
(iv) How could the CAR model given above be simplified to the intrinsic CAR model for
strong spatial autocorrelation? Provide the mathematical expression of the new model after
simplification.
[2]
2.2 Briefly compare spatial Lag and Spatial error models.
[4]
Question 3 [33 marks]
3.1 Distinguish between strict stationarity, second order stationarity, and intrinsic hypotheses of
a regionalised variable.
[6]
3.2 Suppose that using two points on a straight line the value at a third point is to be estimated.
The points are s 1 = 1 ands 2 = -2 . The point for which the estimation is to be done is
s0 = 0. Fig.1 shows the data configuration. Let the measurement values be Z(s 1) = 2 and
Z(s 2) = 4. Suppose the variogram is linear, that ,(h) = h
So
s
.1
Figure 1: Data configuration 1
Use ordinary kriging to estimate Z(s 0 ) and o-bk(s0 ) (the estimated variance).
[6]
3.3 Let {Z(s) : s ED}, D c 3t be a geostatistical process with a wave covariance function given
by
Derive:
(a) the expression of a wave semi-variogram function,
[5]
(b) the correlation function for pz (h).
[3]
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3.4 Let {Z(s) : s E D} be an intrinsically stationary random function with known vari-
ogram function ,(h).
(a) Show that the predictor for ordinary kriging at unsampled location s0 defined by
Ln
ZoK(so) = WiZ(si)
i=l
is unbiased Estimator.
[3]
(b) Show that the variance of the prediction error is given by
(11= Var(ZoK(so) - Z(so)) = -
~7=1 WiWj1(si - Sj) + 2
wn(si - so)
Hint:
=LL L n n
n
WiWjZ(si)Z(sj) - 2 wiZ(si)Z(s 0 ) + (Z(s 0 )) 2
i=l j=l
i=l
[10]
Question 4 [27 marks]
4.1 Let Z be a spatial point process in a spatial domain D E ~ 2 .
(a) Explain what is meant by saying that Z is:
(1) a Homogeneous Poisson Process(HPP).
[3]
(2) a regular process
[2]
(b) Describe briefly the difference between a marked and unmarked spatial point process [2]
4.2 Assume that Z is a Homogeneous Poisson Process(HPP) in a spatial domain D C ~ 2• Use the
maximum likelihood estimation method to show the constant first order intensity function ,\\
1. sgi.ven by /\\\\ -- 7Z(1D5) 1-- ]Dn
[10]
4.3 Consider a spatial point process Z = {Z(A) : AC D}, where Dis the domain of interest.
(a) One hypothesis test of quantifying whether an observed spatial point pattern is com-
pletely spatially random is based on quadrat counts, write down the null and alternative
hypotheses for this test, the test statistic, and the distribution of the test statistic under the
null hypothesis.
[4]
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(b) Consider the following point process of n = 101 points, split into 9 quadrats containing 3
rows and 3 columns as shown if Figure.2. Use the method of quadrat counts to test whether
the data are drawn from a complete spatial random process(show all steps involved in the
hypothesis testing process). .
[6]
..
8
..
•J
•.
Figure 2: Distribution points partioned into 9 quadrats
END OF QUESTION PAPER
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The Chi-Square Distribution
x2
rdf\\p 1 .995
I .990
.975
.950
.9oo
I .750
.5oo
.250
I .100
.o5o
.025
.010
.005
1110.00004
I I I I I I I I I I I 0.00016 0.00098 0.00393 0.01579 0.10153 o.45494 1u2330 2.10554 3.84146 5.02389 6.63490 7.87944
1 I I 2 0.01003 lo.02010 lo.05064 10.10259 lo.21012 lo.57536 1.38629 2.77259 4.60517 15.99146 17.37776 19.21034 110.59663
13 I I I I I I I I I I lo.01112 0.11483 0.21580 0.35185 0.58437 1.21253 2.36597 4.10834 6.25139 7.81473 9.34840 I 1.34487 12.83816
1410.20699
I I I I I I I I I I 0.29711 0.48442 0.71072 1.06362 1.92256 3.35669 5.38527 7.77944 9.48773 11.14329 13.27670 14.86026
1510.41114
[T lo.67573
I I I I I 0.55430 0.83121 1.14548 1.61031 2.67460 4.35146 6.62568
I o.87209 1.23734 1.63538 12.20413 13.45460 15.34812 7.84080
I I I 9.23636 I 1.07050 12.83250 15.08627 116.74960
10.64464112.59159114.44938116.81189118.54758
1110.98926
I I I I I I 1.23904 1.68987 2.16735 2.83311 4.25485 6.34581 9.03715 12.01104 14.06714 116.01216 18.47531 120.21114
1811.34441.
I 1.64650 1~-17973 2.73264 13.48954 15.07064 17.34412 10.21885 13.36157115.50731 17.53455120.09024121.95495
1911.73493
I 2.08790 2.10039
11D I 12.15586 2.55821 3.24697
11112.60322 3.05348 13.81575
11213.07382 3.57057 14.40379
j 13 13.56503 J4.10692 5.00875
I I I I I I 3.32511 4.16816 5.89883 8.34283 11.38875 14.68366 116.91898 19.02211 21.66599 23.58935
I I I I I 3.94030 4.86518 6.73720 9.34182 12.54886 15.98718 18.30104120.48318 23.20925 25.18818
I1
4.57481 15.57778 11.58414 10.34100 13.10069111.21501i19.67514121.92005124.72497126.75685
I I I I 5.22603 16.30380 18.43842 11.34032·1 14.84540 18.54935 21.02601 23.33666 26.21697 128.29952
5.89186 17.04150 19.29907 12.33976 j15.9839I 119.81193122.36203124.73560127.68825129.81947
14.07467 14.66043 5.62873 j6.57063 17.78953 110.16531 13.33927, 17.11693121.06414123.68479126.11895129.14124 j3L31935
I 11514.60092 5.22935
11I65_14221 15.81221
11'715.69722
11816.26480
16.40776
I1.01491
6.26214
6.90766
7.56419
8.23075
I I I I I I I I I 7.26094 8.54676 11.03654 14.33886 18.24509 22.30713 24.99579 27.48839 30.57791 32.80132
11.96165 19.31224 111.91222 15.33850119.36886123.54183126.29623128.84535131.99993134.26719
I 18.67176 10.08519112.19193 16.33818120.48868124.76904121.58111 130.19101 133.40866 135.71847
I i I I I I i 9.39046 110.86494 113.67529 11.33790 21.60489 25.98942 28.86930 31.52638 34.80531 37.15645
I I I 11916.84397 17.63273 8.90652 10.11101 11.65091 14.56200 18.33765122.71781 127.20357130.14353132.85233136.19087138.58226
fzo I I I 17.43384 18.26040 9.59078 10.85081 12.44261 15.45177 19.33743123.82769128.41198131.41043134.16961137.56623139.99685
12118.03365
12218.64272
12319.26042
I I I 8.89720 10.28290 11.59131 13.23960 16.34438 20.33723,24.93478129.61509132.67057135.47888138.93217141.40106
I 9.54249 10.98232112.33801 14.04149117.23962 21.33704126.03927130.81328133.92444136.78071 140.28936142.79565
I 10.19572, ll.68855113.09051 14.84796118.13730 ,22.33688i27.l4134132.00690135.17246138.07563141.63840144.18128
I I I I I )24-19.88623 10.85636 12.40115 13.84843 15.65868 19.03725 23.33673 28.24115 133.19624 36.41503 39.36408 42.97982 45.55851
12I510.51965 11.52398 13.11972114.61141 16.47341119.93934 24.33659 29.33885134.38159137.65248 40.64647 44.31410146.92789
126111.16024
I 12.19815 13.84390 15.37916 17.29188120.84343 25.33646 30.43457135.56317138.88514 41.92317 45.64168148.28988
12I1 I I I I 11.30759 12.87850 14.57338 16.15140 18.11390 21.14940 26.33634 31.52841 36.74122 40.11321 43.19451 46.96294 149.64492
I I I I I izsl 12.46134 13.56471 15.30786 16.92788 18.93924 22.65716 21.33623 32.62049 37.91592 41.33714 44.46079 48.27824 50.99338
12I9 I I I I 13.12115 14.25645 16.04707 11.10837 19.76774 23.56659 28.33613 33.11091 39.08747 42.55697 45.12229 49.58788 !52.33562
l30I I I I I 13.78672 14.95346 16.79077 18.49266 20.59923 24.47761 29.33603 34.79974 40.25602 43.77297 46.97924 50.89218 !53.67196